229.84^2+461.37^2=c^2

Solution for 229.84^2+461.37^2=c^2 equation:

229.84^2+461.37^2=c^2

We move all terms to the left:

229.84^2+461.37^2-(c^2)=0

We add all the numbers together, and all the variables

-1c^2+265688.7025=0

a = -1; b = 0; c = +265688.7025;
Δ = b2-4ac
Δ = 02-4·(-1)·265688.7025
Δ = 1062754.81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1062754.81}}{2*-1}=\frac{0-\sqrt{1062754.81}}{-2}
=-\frac{\sqrt{}}{-2}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1062754.81}}{2*-1}=\frac{0+\sqrt{1062754.81}}{-2}
=\frac{\sqrt{}}{-2}
$